Our code won’t always be able to run without issue. So many things can go wrong when running code — network connectivity can fail, file system permissions can be wrong, bad inputs can be passed to our scripts. Thankfully, we can normally tell when these types of issues *might* happen in our code and we can handle them. In this hands-on lab, we’ll add exception handling to an existing script that can run into many of these issues. To feel comfortable completing this lab, you’ll want to know how to perform exception handling in Python (watch the “Handling Exceptions with `try`, `except`, `else`, and `finally`” video from the Certified Associate in Python Programming Certification course).
Learning Objectives
Successfully complete this lab by achieving the following learning objectives:
- Add Exception Handling Around Setting the `name` Variable
The first expression in the
exception_handling.py
script reads fromsys.argv
, which is a list. If the script is run without any additional positional arguments, there won’t be an item at the index of1
and we’ll receive anIndexError
. Let’s add exception handling around this line to catch the error, print an error message about the number of required arguments, and then usesys.exit(1)
to stop the script and exit with a non-zero status code.~/exception_handling.py
import sys # 1) Fetch name from the first argument passed to the script. # If there is no argument, then exist with a readable error message. # The potential error here is an IndexError. try: name = sys.argv[1] except IndexError: print("Error: please provide a name and a repeat count to the script.") sys.exit(1) # Remainder of file omitted
Now if we run the script without any arguments, we should see this error message:
$ python3.7 exception_handling.py Error: please provide a name and a repeat count to the script. $ python3.7 exception_handling.py Kevin Traceback (most recent call last): File "exception_handling.py", line 16, in <module> repeat_count = int(sys.argv[2]) IndexError: list index out of range
This next error is related to the next bit of logic in the script.
- Handle Potential `ValueError` and `IndexError` When Setting `repeat_count` Variable
When we set the
repeat_count
variable, we indexsys.argv
at the index of2
so we can once again run into anIndexError
. In that case, we’ll want to provide the same error message we did for thename
variable. Additionally, we can also run into aValueError
if the value provided cannot be cast to an integer, so we’ll need to have a secondexcept
statement that handles that and provides a more useful error message.~/exception_handling.py
# previous code omitted # 2) Convert the second argument to be an integer so that we can repeatedly print out # the name argument. We should either a ValueError or an IndexError if there weren't enough # arguments provided. try: repeat_count = int(sys.argv[2]) except IndexError: print("Error: please provide a name and a repeat count to the script.") sys.exit(1) except ValueError: print("Error: the repeat count needs to be a number.") sys.exit(1) # remaining code omitted
- Handle Potential File IO Errors When Writing to `name_repeated.txt`
The last section of this script deals with interacting with a file, so there are numerous potential errors we could run into. Depending on the version of Python we use to run the script, we could get either an
OSError
or aPermissionError
if we don’t have permissions to interact with a file. To make this script backward-compatible, we’ll catchOSError
sincePermissionError
inherits fromOSError
and would also be caught. Additionally, we’re going to catchIOError
since this is another common error that happens when interacting with files. These error types will both be caught by the sameexcept
statement. Our requirements state that we need to print to the screen if we can’t write to a file, and we’re going to keep ourtry
block small by writing to the file in theelse
branch if we can read from it.~/exception_handling.py
# previous code omitted # 3) Open a file called `name_repeated.txt` in the `root_files` directory and write a line for each time the name was # repeated. If the user running the script doesn't have write permissions for the directory that # we're writing to then we might see a PermissionError. PermissionError is new as of 3.3, so let's instead catch # OSError and IOError to make the script more backward compatible. If an error is caught print to the screen instead. try: f = open("root_files/name_repeated.txt", "w") except (OSError, IOError) as err: print("Error: unable to write file (", err, ")") for i in range(1, repeat_count + 1): print(i, "-", name) else: names = [name + "n" for i in range(1, repeat_count + 1)] f.writelines(names) f.close()
Now we’ve successfully handled all the common errors we might run into when running this script.